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Proof step 13 from proof write-other-true (previous step)

rs1 ∩ rs0 = ∅, a[P](mk(rs1, f(r; o), g)) ⊦ g(r) = a, (a[P] * true)[rs1 ∪ rs0, f, g], a[P](mk(rs1, f, g))

User applied rule cut formula

And obtained the following new goals

Proof step 14:
rs1 ∩ rs0 = ∅, a[P](mk(rs1, f(r; o), g)) ⊦ g(r) = a, mk(rs1, f(r; o), g) = mk(rs1, f, g), a[P](mk(rs1, f, g)), (a[P] * true)[rs1 ∪ rs0, f, g]

Rule argument

fma: mk(rs1, f(r; o), g) = mk(rs1, f, g)

Additional information

Used formulas: mk(rs1, f(r; o), g) = mk(rs1, f, g)