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Proof step 17 from proof write-other-true (previous step)

rs1 ∩ rs0 = ∅, a[P](mk(rs1, f(r; o), g)), r0 ∈ rs1 ⊦ # rs1 = 0, (r = r0 ⊃ o;f(r0)) = f(r0), g(r) = a, rs1 = ∅, (a[P] * true)[rs1 ∪ rs0, f, g], a[P](mk(rs1, f, g))

User applied rule case distinction

And obtained the following new goals

Proof step 18:
r = r0, rs1 ∩ rs0 = ∅, a[P](mk(rs1, f(r; o), g)), r0 ∈ rs1 ⊦ # rs1 = 0, g(r) = a, o = f(r0), rs1 = ∅, a[P](mk(rs1, f, g)), (a[P] * true)[rs1 ∪ rs0, f, g]

Rule argument

pos: right 2

Proof step 17 from proof write-other-true (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information