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Proof step 5 from proof write-unknown (previous step)

⊦ (∃ o. (a[r => o] * R)[rs, f, g]) ↔ (a[r => o1] * R)[rs, f(r; o1), g]

User applied rule case distinction

And obtained the following new goals

Proof step 6:
∃ o. (a[r => o] * R)[rs, f, g] ⊦ (a[r => o1] * R)[rs, f(r; o1), g]
Proof step 9:
(a[r => o1] * R)[rs, f(r; o1), g] ⊦ ∃ o. (a[r => o] * R)[rs, f, g]

Rule argument

pos: right 1

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