⊦ P0(H0) ∧ P1(H1) ∧ H0 ⊥ H1 → ((P0 * P1))(H0 ∪ H1)
P(H0), Pa(a)(H1), H1 ⊥ H0 ⊦ ((_∃ Pa * P))(H1 ∪ H0), (_∃ Pa)(H1) ∧ P(H0) ∧ H1 ⊥ H0
Used terms: H0, H1, P, _∃ Pa