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Proof step 1 from proof at-unil (conclusion)
⊦ rs0 ∩ rs1 = ∅ ∧ r ∈ rs0 → (mk(rs0, f0) ∪ mk(rs1, f1))[r] = f0(r)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
rs0 ∩ rs1 = ∅, r ∈ rs0 ⊦ (mk(rs0, f0) ∪ mk(rs1, f1))[r] = f0(r)
Rule argument
Additional information