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Proof step 5 from proof mapex-in (previous step)

∃ H0, H1. H0 ⊥ H1 ∧ mk(rs, f) = H0 ∪ H1 ∧ r =>_(H0) ∧ P(H1) ⊦ r ∈ rs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information