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Proof step 5 from proof mapex-put (previous step)

((r => o * P))(mk(rs, f)[r, o]), r ∈ rs ⊦ # rs = 0, rs = ∅, ∃ o. ((r => o * P))(mk(rs, f))

User applied rule exists right

And obtained the following new goals

Proof step 6:
((r => o * P))(mk(rs, f)[r, o]), r ∈ rs ⊦ # rs = 0, rs = ∅, ((r => f(r) * P))(mk(rs, f)), ∃ o. ((r => o * P))(mk(rs, f))

Rule argument

pos: right 3 terms: f(r) abort: F discard: F computed: F

Additional information

Used terms: f(r)