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Proof step 3 from proof mk-exists (previous step)

∀ H0. # H0 < # H → true → (∃ rs, f. H0 = mk(rs, f)) ⊦ ∃ rs, f. H = mk(rs, f)

User applied rule cut formula

And obtained the following new goals

Proof step 4:
H = ∅, ∀ H0. # H0 < # H → true → (∃ rs, f. H0 = mk(rs, f)) ⊦ ∃ rs, f. H = mk(rs, f)
Proof step 6:
∀ H0. # H0 < # H → true → (∃ rs, f. H0 = mk(rs, f)) ⊦ H = ∅, ∃ rs, f. H = mk(rs, f)

Rule argument

fma: H = ∅

Additional information

Used formulas: H = ∅