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Proof step 5 from proof mk-exists (previous step)

∀ H0. # H0 < # ∅ → true → (∃ rs, f. H0 = mk(rs, f)) ⊦ ∃ rs, f. ∅ = mk(rs, f)

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: ∅, f abort: F discard: F computed: F

Additional information

Used simplifier rules: emp: ⊦ mk(∅, f) = ∅; Used terms: ∅, f