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Proof step 1 from proof mk-ext (conclusion)

⊦ P0 = P1 ↔ (∀ rs, f. P0[rs, f] ↔ P1[rs, f])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
∀ rs, f. P0(mk(rs, f)) ↔ P1(mk(rs, f)) ⊦ P0 = P1

Rule argument

Additional information

Used simplifier rules: apply: ⊦ P[rs, f] ↔ P(mk(rs, f));