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Proof step 22 from proof sep (previous step)

mk(rs, f) = mk(rs0, f0) ∪ mk(rs1, f1), rs0 ∩ rs1 = ∅, P0(mk(rs0, f0)), P1(mk(rs1, f1)) ⊦ P0(mk(rs0, f))

User applied rule cut formula

And obtained the following new goals

Proof step 23:
mk(rs, f) = mk(rs0, f0) ∪ mk(rs1, f1), rs0 ∩ rs1 = ∅, P0(mk(rs0, f0)), P1(mk(rs1, f1)) ⊦ mk(rs0, f) = mk(rs0, f0), P0(mk(rs0, f))

Rule argument

fma: mk(rs0, f) = mk(rs0, f0)

Additional information

Used formulas: mk(rs0, f) = mk(rs0, f0)