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Proof step 1 from proof uni (conclusion)
⊦ rs0 ∩ rs1 = ∅ → mk(rs0 ∪ rs1, f) = mk(rs0, f) ∪ mk(rs1, f)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
rs0 ∩ rs1 = ∅ ⊦ mk(rs0 ∪ rs1, f) = mk(rs0, f) ∪ mk(rs1, f)
Rule argument
Additional information