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Proof step 13 from proof modify+-sym (previous step)

rtc(n0 +1, modify(rs))(H0, H1), ∀ rs, H0, H1. rtc(n0, modify(rs))(H0, H1) → rtc(n0, modify(rs))(H1, H0) ⊦ rtc(n0 +1, modify(rs))(H1, H0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
rtc(n0 + 1, modify(rs))(H0, H1), ∀ rs, H0, H1. rtc(n0, modify(rs))(H0, H1) → rtc(n0, modify(rs))(H1, H0) ⊦ rtc(n0 + 1, modify(rs))(H1, H0)

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)