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Proof step 24 from proof modify+-sym (
previous step
)
modify(rs)(H, H0), rtc(n0, modify(rs))(H, H1), ∀ rs, H0, H1. rtc(n0, modify(rs))(H0, H1) → rtc(n0, modify(rs))(H1, H0) ⊦ rtc(n0, modify(rs))(H1, H)
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 3 terms: rs, H, H1
Additional information
Used terms: rs, H, H1