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Proof step 19 from proof modify-agree (
previous step
)
⊦ ((H0 ≡ H1))(rs) ↔ (∀ r. r ∈ rs → (r ∈ H0 ↔ r ∈ H1) ∧ (r ∈ H0 → H0[r] = H1[r]))
Lemma
agree