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Proof step 24 from proof modify-agree (previous step)

modify(rs)(H0, H), r ∈ rs, r ∈ rs → (r ∈ H ↔ r ∈ H1) ∧ (r ∈ H → H[r] = H1[r]) ⊦ # rs = 0, rs = ∅, (r ∈ H0 ↔ r ∈ H1) ∧ (r ∈ H0 → H0[r] = H1[r])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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