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Proof step 30 from proof modify-agree (previous step)

(H0 ++ r0)[r] = H1[r], r ∈ rs, r ∈ H0, r ∈ H1 ⊦ # rs = 0, H0[r] = H1[r], r0 = null, rs = ∅, r0 ∈ rs, r0 ∈ H0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 31:
r ∈ H, r0 ≠ null, ¬ r0 ∈ H ⊦ r ≠ r0 → (H ++ r0)[r] = H[r]

Rule argument

spec: heap name: at-alloc seq: r ∈ H, r0 ≠ null, ¬ r0 ∈ H ⊦ r ≠ r0 → (H ++ r0)[r] = H[r] subst: [r, r0, H] → [r, r0, H0] flags: <all paths>

Additional information

Used terms: r, r0, H0