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Proof step 8 from proof modify-agree (previous step)

rtc(0, modify(rs))(H0, H1) ⊦ ((H0 ≡ H1))(rs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ ((H1 ≡ H1))(rs)

Rule argument

Additional information

Used simplifier rules: ⊦ rtc(0, PHH)(H, H0) ↔ H = H0; (s)