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Proof step 6 from proof modify-footprint (
previous step
)
modify(rs)(H0, H1), modify*(rs)(H0, H1) → (P(H0) ↔ P(H1)) ⊦ P(H0) ↔ P(H1)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 7
:
modify(rs)(H0, H1) ⊦ P(H0) ↔ P(H1), modify*(rs)(H0, H1)
Rule argument
Additional information