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Proof step 12 from proof modify-sym (previous step)

⊦ r = null, r ∈ H0, r ∈ rs, rtc(1, modify(rs))(H0 ++ r, H0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
⊦ r = null, r ∈ H0, r ∈ rs, modify(rs)(H0 ++ r, H0)

Rule argument

Additional information

Used simplifier rules: rtc1: ⊦ rtc(1, PHH)(H, H0) ↔ PHH(H, H0); from specification rtc[rtc-heap]