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Proof step 14 from proof modify-sym (previous step)

⊦ modify(rs)(H0, H1) ↔ (∃ r. ¬ r ∈ rs ∧ r ≠ null ∧ ¬ r ∈ H0 ∧ H1 = H0 ++ r) ∨ (∃ r, o. ¬ r ∈ rs ∧ r ∈ H0 ∧ H1 = H0[r, o]) ∨ (∃ r. ¬ r ∈ rs ∧ r ∈ H0 ∧ H1 = H0 -- r)

Lemma modify