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Proof step 15 from proof modify-sym (previous step)

⊦ r = null, r ∈ H0, r ∈ rs, (∃ r0. ¬ r0 ∈ rs ∧ r0 ≠ null ∧ ¬ r0 ∈ H0 ++ r ∧ H0 = H0 ++ r ++ r0) ∨ (∃ r0, o. ¬ r0 ∈ rs ∧ r0 ∈ H0 ++ r ∧ H0 = (H0 ++ r)[r0, o]) ∨ (∃ r0. ¬ r0 ∈ rs ∧ r0 ∈ H0 ++ r ∧ H0 = (H0 ++ r) -- r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: in-alloc: r0 ≠ null, ¬ r0 ∈ H ⊦ r ∈ H ++ r0 ↔ ¬ ¬(r = r0 ∨ r ∈ H); from specification heap