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Proof step 23 from proof modify-sym (previous step)

r0 ∈ H0 ⊦ r0 ∈ rs, ∃ r. ¬ r ∈ rs ∧ r ≠ null ∧ ¬ r ∈ H0 ∧ H0 = H0[r0, o] ++ r, ∃ r, o0. ¬ r ∈ rs ∧ r ∈ H0 ∧ H0 = H0[r0, o][r, o0], ∃ r. ¬ r ∈ rs ∧ r ∈ H0 ∧ H0 = H0[r0, o] -- r

User applied rule exists right

And obtained the following new goals

Proof step 24:
r0 ∈ H0 ⊦ r0 ∈ rs, ∃ r. ¬ r ∈ rs ∧ r ≠ null ∧ ¬ r ∈ H0 ∧ H0 = H0[r0, o] ++ r, ¬ r0 ∈ rs ∧ r0 ∈ H0 ∧ H0 = H0[r0, o][r0, H0[r0]], ∃ r. ¬ r ∈ rs ∧ r ∈ H0 ∧ H0 = H0[r0, o] -- r

Rule argument

pos: right 3 terms: r0, H0[r0] abort: F discard: T computed: F

Additional information

Used terms: r0, H0[r0]