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Proof step 5 from proof And-prop-inj (
previous step
)
bv → P0 = P1 ⊦ (⌜bv⌝ ∧ P0) = (⌜bv⌝ ∧ P1)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
⊦ (⌜false⌝ ∧ P0) = (⌜false⌝ ∧ P1)
Rule argument
Additional information