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Proof step 1 from proof Eq-P (conclusion)
⊦ P0 = P1 ↔ (∀ P, H. ((P0 * P))(H) ↔ ((P1 * P))(H))
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
∀ P, H. ((P0 * P))(H) ↔ ((P1 * P))(H) ⊦ P0 = P1
Rule argument
Additional information