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Proof step 4 from proof Imp-from-eq (
previous step
)
P0(H) → P1(H), ∀ H. P0(H) → P1(H), ∀ H. P1(H) → P0(H) ⊦ P0(H) ↔ P1(H)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
P1(H), ∀ H. P1(H) → P0(H), ∀ H. P0(H) → P1(H) ⊦ P0(H)
Rule argument
Additional information