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Proof step 1 from proof Imp2 (conclusion)

⊦ P0 ⊆ P1 ∧ ((P * P0))(H) → ((P * P1))(H)

System applied rule normalize

And obtained the following new goals

Proof step 2:
((P * P0))(H), P0 ⊆ P1 ⊦ ((P * P1))(H)

Rule argument

Additional information