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Proof step 5 from proof Imp2 (previous step)

∀ H. P0(H) → P1(H), ∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P(H0) ∧ P0(H1) ⊦ ((P * P1))(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information