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Proof step 1 from proof adjunction (conclusion)

⊦ (∀ H. ((P0 → P1 -* P2))(H)) ↔ (∀ H. ((P0 * P1 → P2))(H))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ (∀ H. P0(H) → ((P1 -* P2))(H)) ↔ (∀ H. ((P0 * P1))(H) → P2(H))

Rule argument

Additional information

Used simplifier rules: imp: ⊦ ((P0 → P1))(H) ↔ P0(H) → P1(H);