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Proof step 13 from proof adjunction (
previous step
)
P0(H1), P1(H0), P2(H0 ∪ H1), H1 ⊥ H0, ∀ H0. H0 ⊥ H1 ∧ P1(H0) → P2(H0 ∪ H1) ⊦ P2(H1 ∪ H0)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 14
:
⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1
Rule argument
spec: heap name: uni-com seq: ⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1 subst: [H0, H1] → [H1, H0] flags: <all paths>
Additional information
Used terms: H1, H0