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Proof step 15 from proof adjunction (
previous step
)
∀ H. ((P0 * P1))(H) → P2(H) ⊦ ∀ H. P0(H) → ((P1 -* P2))(H)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 16
:
P0(H), ∀ H. ((P0 * P1))(H) → P2(H) ⊦ ((P1 -* P2))(H)
Rule argument
Additional information