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Proof step 8 from proof adjunction (
previous step
)
P0(H1), P1(H0), H1 ⊥ H0, P0(H1) → ((P1 -* P2))(H1) ⊦ P2(H1 ∪ H0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 9
:
((P1 -* P2))(H1), P0(H1), P1(H0), H1 ⊥ H0 ⊦ P2(H1 ∪ H0)
Rule argument
Additional information