⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1
P0(H0), P1(H0), precise(P0), H ⊥ H0, H0 ⊥ H ⊦ (((P0 ∧ P1) * P))(H0 ∪ H) ↔ P(H)
Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s) Used terms: H0, H