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Proof step 1 from proof and-weaken (conclusion)

∀ H. ((P1 → P0))(H) ⊦ (P0 ∧ P1) = P1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
∀ H. P1(H) → P0(H) ⊦ (P0 ∧ P1) = P1

Rule argument

Additional information

Used simplifier rules: imp: ⊦ ((P0 → P1))(H) ↔ P0(H) → P1(H);