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Proof step 2 from proof contract-wand (previous step)

⊦ ((P0 * (P0 -* P1)))(H) ↔ ((P0 * (P0 -* P1) ∧ P1))(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
((P0 * (P0 -* P1)))(H) ⊦ P1(H)

Rule argument

Additional information

Used simplifier rules: and: ⊦ ((P0 ∧ P1))(H) ↔ P0(H) ∧ P1(H);%and-ass: ⊦ ((P0 ∧ P1) ∧ P2) = (P0 ∧ P1 ∧ P2);%and-com: ⊦ (P0 ∧ P1) = (P1 ∧ P0);