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Proof step 2 from proof false-sep (previous step)

⊦ ((false * P))(H) ↔ false(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
((⌜false⌝ * P))(H) ⊦

Rule argument

Additional information

Used simplifier rules: false: ⊦ false = ⌜false⌝ ;%prop: ⊦ ⌜bv⌝ (H) ↔ bv;