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Proof step 4 from proof imp-mono (previous step)

∀ H. P(H) → P0(H), ∃ H2, H1. H2 ⊥ H1 ∧ H0 = H2 ∪ H1 ∧ P(H2) ∧ P1(H1) ⊦ ((P0 * P1))(H0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
P(H1), P1(H), H1 ⊥ H, ∀ H. P(H) → P0(H) ⊦ ((P0 * P1))(H1 ∪ H)

Rule argument

Additional information