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Proof step 26 from proof introduce-sharing (previous step)

∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ ((P -* P0))(H0) ∧ (((P -* P1) * P))(H1) ⊦ ((P0 ⊗ P1))(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
(((P -* P1) * P))(H0), ((P -* P0))(H1), H1 ⊥ H0 ⊦ ((P0 ⊗ P1))(H1 ∪ H0)

Rule argument

Additional information