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Proof step 29 from proof introduce-sharing (previous step)

((P -* P0))(H1), H1 ⊥ H0, ∃ H2, H1. H2 ⊥ H1 ∧ H0 = H2 ∪ H1 ∧ ((P -* P1))(H2) ∧ P(H1) ⊦ ((P0 ⊗ P1))(H1 ∪ H0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
((P -* P0))(H1), ((P -* P1))(H2), P(H), H2 ⊥ H, H1 ⊥ H2, H1 ⊥ H ⊦ ((P0 ⊗ P1))(H1 ∪ H2 ∪ H)

Rule argument

Additional information

Used simplifier rules: ⊦ H1 ⊥ H → (H0 ⊥ H1 ∪ H ↔ H0 ⊥ H1 ∧ H0 ⊥ H); (ws)