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Proof step 38 from proof introduce-sharing (previous step)

P(H), P0(H ∪ H1), H1 ⊥ H, H1 ⊥ H2, H2 ⊥ H, ∀ H1. H1 ⊥ H2 ∧ P(H1) → P1(H1 ∪ H2) ⊦ ∃ H0, H3, H4. H0 ⊥ H4 ∧ H0 ⊥ H3 ∧ H3 ⊥ H4 ∧ H1 ∪ H2 ∪ H = H0 ∪ H3 ∪ H4 ∧ P0(H0 ∪ H4) ∧ P1(H3 ∪ H4)

User applied rule all left

And obtained the following new goals

Proof step 39:
P(H), P0(H ∪ H1), H2 ⊥ H, H1 ⊥ H2, H1 ⊥ H, H ⊥ H2 ∧ P(H) → P1(H ∪ H2) ⊦ ∃ H0, H3, H4. H0 ⊥ H4 ∧ H0 ⊥ H3 ∧ H3 ⊥ H4 ∧ H1 ∪ H2 ∪ H = H0 ∪ H3 ∪ H4 ∧ P0(H0 ∪ H4) ∧ P1(H3 ∪ H4)

Rule argument

pos: left 6 terms: H abort: F discard: T computed: F

Additional information

Used terms: H