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Proof step 2 from proof precise-sep (
previous step
)
precise(P0), precise(P1) ⊦ precise(P0 * P1)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
precise(P1), precise(P0) ⊦ precise(P0 * P1)
Rule argument
Additional information