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Proof step 1 from proof precise-split-l (conclusion)

precise(P0) ⊦ P0(H0) ∧ H0 ⊥ H1 → (((P0 * P1))(H0 ∪ H1) ↔ P1(H1))

System applied rule normalize

And obtained the following new goals

Proof step 2:
P0(H0), precise(P0), H0 ⊥ H1 ⊦ ((P0 * P1))(H0 ∪ H1) ↔ P1(H1)

Rule argument

Additional information