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Proof step 3 from proof precise-split-r (previous step)

((P0 * P1))(H0 ∪ H1), P1(H1), precise(P1), H0 ⊥ H1 ⊦ P0(H0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1
Proof step 5:
((P0 * P1))(H1 ∪ H0), P1(H1), precise(P1), H0 ⊥ H1, H1 ⊥ H0 ⊦ P0(H0)

Rule argument

spec: heap name: uni-com seq: ⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1 subst: [H0, H1] → [H1, H0] flags: <all paths>

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s) Used terms: H1, H0