precise(P0) ⊦ P0(H0) ∧ H0 ⊥ H1 → (((P0 * P1))(H0 ∪ H1) ↔ P1(H1))
Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s) Used terms: H0, H1, P0, P1