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Proof step 4 from proof sep-Mp (previous step)

∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P0(H0) ∧ ((P0 -* P1))(H1) ⊦ P1(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information