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Proof step 14 from proof sep-ass (previous step)

P0(H2), P1(H), P2(H0), H0 ⊥ H, H2 ⊥ H, H0 ⊥ H2 ⊦ ((P0 * P1 * P2))(H2 ∪ H ∪ H0), P0(H2) ∧ ((P1 * P2))(H ∪ H0) ∧ H2 ⊥ H ∪ H0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information