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Proof step 28 from proof sep-ass (previous step)

P0(H1), P1(H2), P2(H), H1 ⊥ H, H1 ⊥ H2, H2 ⊥ H, H ⊥ H1 ⊦ (((P0 * P1) * P2))((H1 ∪ H2) ∪ H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
P0(H1), P1(H2), P2(H), H2 ⊥ H, H1 ⊥ H2, H1 ⊥ H ⊦ (((P0 * P1) * P2))((H1 ∪ H2) ∪ H)

Rule argument

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s)