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Proof step 6 from proof sep-com (previous step)

P0(H1), P1(H0), H1 ⊥ H0 ⊦ ((P1 * P0))(H1 ∪ H0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1
Proof step 8:
P0(H1), P1(H0), H1 ⊥ H0, H0 ⊥ H1 ⊦ ((P1 * P0))(H0 ∪ H1)

Rule argument

spec: heap name: uni-com seq: ⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1 subst: [H0, H1] → [H0, H1] flags: <all paths>

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s) Used terms: H0, H1