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Proof step 9 from proof sep-com (previous step)

P0(H1), P1(H0), H1 ⊥ H0 ⊦ ((P1 * P0))(H0 ∪ H1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ P0(H0) ∧ P1(H1) ∧ H0 ⊥ H1 → ((P0 * P1))(H0 ∪ H1)

Rule argument

spec: <toplevel> name: split-union seq: ⊦ P0(H0) ∧ P1(H1) ∧ H0 ⊥ H1 → ((P0 * P1))(H0 ∪ H1) subst: [H1, H0, P1, P0] → [H1, H0, P0, P1] flags: <all paths>

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s) Used terms: H1, H0, P0, P1