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Proof step 11 from proof sep-inj2-imp (previous step)

P0(H1), P2(H0), H1 ⊥ H0, ∀ H. P0(H) → P1(H), ∀ H. P2(H) → P3(H) ⊦ ((P1 * P3))(H1 ∪ H0), P3(H0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: H0

Additional information

Used terms: H0